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Definitions of Trigonometric Functions
By James D. Thomas

Draw a unit circle with center O. Let a central angle with initial side OP and
terminal side OQ contain x radians (that is, the arc PQ has length x). Drop a
perpendicular from Q to OP meeting it at R. Then OR = cos(x) and RQ = sin(x). If
those directed line segments are up or to the right, the lengths are positive.
If they are down or to the left, the lengths are negative.
Values at special angles: x sin(x) cos(x) tan(x) cot(x) sec(x) csc(x)
0 0 1 0 --- 1 ---
/6 1/2 sqrt(3)/2 sqrt(3)/3 sqrt(3) 2 sqrt(3)/3 2
/4 sqrt(2)/2 sqrt(2)/2 1 1 sqrt(2) sqrt(2)
/3 sqrt(3)/2 1/2 sqrt(3) sqrt(3)/3 2 2 sqrt(3)/3
/2 1 0 --- 0 --- 1
2 /3 sqrt(3)/2 -1/2 -sqrt(3) -sqrt(3)/3 -2 2 sqrt(3)/3
3 /4 sqrt(2)/2 -sqrt(2)/2 -1 -1 -sqrt(2) sqrt(2)
5 /6 1/2 -sqrt(3)/2 -sqrt(3)/3 -sqrt(3) -2 sqrt(3)/3 2
0 -1 0 --- -1 ---
More values at special angles: x /10 /5
sin(x) (-1+sqrt[5])/4 sqrt(10-2 sqrt[5])/4
cos(x) sqrt(10+2 sqrt[5])/4 (1+sqrt[5])/4
tan(x) sqrt(1-2/sqrt[5]) sqrt(5-2 sqrt[5])
cot(x) sqrt(5+2 sqrt[5]) sqrt(1+2/sqrt[5])
sec(x) sqrt(2-2/sqrt[5]) -1+sqrt[5]
csc(x) 1+sqrt[5] sqrt(2+2/sqrt[5])
Use the above values and the identities below to
obtain values of trigonometric functions of the following multiples of /10:
3 /10 = /2 - /5,
2 /5 = /2 - /10,
3 /5 = /2 + /10,
7 /10 = /2 + /5,
4 /5 = - /5,
9 /10 = - /10.

Bounds
|sin(x)| <= 1,
|cos(x)| <= 1,
|sec(x)| >= 1,
|csc(x)| >= 1.

Identities
sec(x) = 1/cos(x),
csc(x) = 1/sin(x),
cot(x) = 1/tan(x),
tan(x) = sin(x)/cos(x),
cot(x) = cos(x)/sin(x).
sin(-x) = -sin(x),
cos(-x) = cos(x),
tan(-x) = -tan(x),
cot(-x) = -cot(x),
sec(-x) = sec(x),
csc(-x) = -csc(x).
sin( /2-x) = cos(x),
cos( /2-x) = sin(x),
tan( /2-x) = cot(x),
cot( /2-x) = tan(x),
sec( /2-x) = csc(x),
csc( /2-x) = sec(x).
sin( /2+x) = cos(x),
cos( /2+x) = -sin(x),
tan( /2+x) = -cot(x),
cot( /2+x) = -tan(x),
sec( /2+x) = -csc(x),
csc( /2+x) = sec(x).
sin( -x) = sin(x),
cos( -x) = -cos(x),
tan( -x) = -tan(x),
cot( -x) = -cot(x),
sec( -x) = -sec(x),
csc( -x) = csc(x).
sin( +x) = -sin(x),
cos( +x) = -cos(x),
tan( +x) = tan(x),
cot( +x) = cot(x),
sec( +x) = -sec(x),
csc( +x) = -csc(x).
sin(2 +x) = sin(x),
cos(2 +x) = cos(x),
tan(2 +x) = tan(x),
cot(2 +x) = cot(x),
sec(2 +x) = sec(x),
csc(2 +x) = csc(x).
sin2(x) + cos2(x) = 1,
tan2(x) + 1 = sec2(x),
1 + cot2(x) = csc2(x).
sin(x+y) = sin(x)cos(y) + cos(x)sin(y),
cos(x+y) = cos(x)cos(y) - sin(x)sin(y),
tan(x+y) = [tan(x)+tan(y)]/[1-tan(x)tan(y)],
cot(x+y) = [cot(x)cot(y)-1]/[cot(x)+cot(y)].
sin(x-y) = sin(x)cos(y) - cos(x)sin(y),
cos(x-y) = cos(x)cos(y) + sin(x)sin(y),
tan(x-y) = [tan(x)-tan(y)]/[1+tan(x)tan(y)],
cot(x-y) = [cot(x)cot(y)+1]/[cot(y)-cot(x)].
sin(2x) = 2 sin(x)cos(x),
cos(2x) = cos2(x) - sin2(x),
= 2 cos2(x) - 1,
= 1 - 2 sin2(x),
tan(2x) = [2 tan(x)]/[1-tan2(x)],
cot(2x) = [cot2(x)-1]/[2 cot(x)].
|sin(x/2)| = sqrt([1-cos(x)]/2),
|cos(x/2)| = sqrt([1+cos(x)]/2),
|tan(x/2)| = sqrt([1-cos(x)]/[1+cos(x)]),
tan(x/2) = [1-cos(x)]/sin(x),
= sin(x)/[1+cos(x)].
sin(3x) = 3 sin(x) - 4 sin3(x),
cos(3x) = 4 cos3(x) - 3 cos(x),
tan(3x) = [3 tan(x)-tan3(x)]/[1-3 tan2(x)].
sin(4x) = 4 sin(x)cos(x)[2 cos2(x)-1],
cos(4x) = 8 cos4(x) - 8 cos2(x) + 1.
sin(5x) = 5 sin(x) - 20 sin3(x) + 16 sin5(x),
cos(5x) = 16 cos5(x) - 20 cos3(x) + 5 cos(x).
sin(6x) = 2 sin(x)cos(x)[16 cos4(x) - 16 cos2(x) + 3],
cos(6x) = 32 cos6(x) - 48 cos4(x) + 18 cos2(x) - 1.
sin(nx) = 2 sin([n-1]x)cos(x) - sin([n-2]x),
cos(nx) = 2 cos([n-1]x)cos(x) - cos([n-2]x),
tan(nx) = (tan[(n-1)x]+tan[x])/(1-tan[(n-1)x]tan[x]).
sin(x)cos(y) = [sin(x+y) + sin(x-y)]/2,
cos(x)sin(y) = [sin(x+y) - sin(x-y)]/2,
cos(x)cos(y) = [cos(x-y) + cos(x+y)]/2,
sin(x)sin(y) = [cos(x-y) - cos(x+y)]/2.
sin(x) + sin(y) = 2 sin[(x+y)/2]cos[(x-y)/2],
sin(x) - sin(y) = 2 cos[(x+y)/2]sin[(x-y)/2],
cos(x) + cos(y) = 2 cos[(x+y)/2]cos[(x-y)/2],
cos(x) - cos(y) = -2 sin[(x+y)/2]sin[(x-y)/2],
tan(x) + tan(y) = sin(x+y)/[cos(x)cos(y)],
tan(x) - tan(y) = sin(x-y)/[cos(x)cos(y)],
cot(x) + cot(y) = sin(x+y)/[sin(x)sin(y)],
cot(x) - cot(y) = -sin(x-y)/[sin(x)sin(y)].
[sin(x)+sin(y)]/[cos(x)+cos(y)] = tan[(x+y)/2],
[sin(x)-sin(y)]/[cos(x)+cos(y)] = tan[(x-y)/2],
[sin(x)+sin(y)]/[cos(x)-cos(y)] = -cot[(x-y)/2],
[sin(x)-sin(y)]/[cos(x)-cos(y)] = -cot[(x+y)/2],
[sin(x)+sin(y)]/[sin(x)-sin(y)] = tan[(x+y)/2]/tan[(x-y)/2].
sin2(x) - sin2(y) = sin(x+y)sin(x-y),
cos2(x) - cos2(y) = -sin(x+y)sin(x-y),
cos2(x) - sin2(y) = cos(x+y)cos(x-y).
sin2(x) = (1 - cos[2x])/2,
cos2(x) = (1 + cos[2x])/2,
tan2(x) = (1 - cos[2x])/(1 + cos[2x]),
sin3(x) = (3 sin[x] - sin[3x])/4,
cos3(x) = (3 cos[x] + cos[3x])/4,
sin4(x) = (3 - 4 cos[2x] + cos[4x])/8,
cos4(x) = (3 + 4 cos[2x] + cos[4x])/8,
sin5(x) = (10 sin[x] - 5 sin[3x] + sin[5x])/16,
cos5(x) = (10 cos[x] + 5 cos[3x] + cos[5x])/16,
sin6(x) = (10 - 15 cos[2x] + 6 cos[4x] - cos[6x])/32,
cos6(x) = (10 + 15 cos[2x] + 6 cos[4x] + cos[6x])/32,

Relations in Right Triangles
In the right triangle ABC with right angle C = /2,
A + B = /2,
c2 = a2 + b2,
sin(A) = cos(B) = a/c,
cos(A) = sin(B) = b/c,
tan(A) = cot(B) = a/b,
cot(A) = tan(B) = b/a,
sec(A) = csc(B) = c/b,
csc(A) = sec(B) = c/a,
ha = b,
hb = a,
hc = ab/c.
Solving Right Triangles
- Case I: You are given a and A.
- B =
/2 - A, c = a csc(A), b = a
cot(A).
- Case II: You are given a and B.
- A =
/2 - B, c = a sec(B), b = a
tan(B).
- Case III: You are given c and A.
- B =
/2 - A, a = c sin(A), b = c
cos(A).
- Case IV: You are given a and b.
- tan(A) = a/b, B =
/2 - A, c = a
csc(A).
- Case V: You are given a and c.
- sin(A) = a/c, B =
/2 - A, b = a cot(A).

Relations in Oblique Triangles
A + B + C = ,
s = (a+b+c)/2, half the perimeter,
r = radius of inscribed circle,
R = radius of circumscribed circle,
K = area.
The Law of Sines: a/sin(A) = b/sin(B) = c/sin(C) = 2R.
This implies that a <= b <= c if and only if A <= B <= C.
The Law of Cosines: a2 = b2 + c2 - 2bc cos(A),
b2 = c2 + a2 - 2ca cos(B),
c2 = a2 + b2 - 2ab cos(C).
The Law of Tangents: (a+b)/(a-b) = tan[(A+B)/2]/tan[(A-B)/2],
(b+c)/(b-c) = tan[(B+C)/2]/tan[(B-C)/2],
(c+a)/(c-a) = tan[(C+A)/2]/tan[(C-A)/2].
Newton's Formulae: (a+b)/c = cos[(A-B)/2]/sin(C/2),
(b+c)/a = cos[(B-C)/2]/sin(A/2),
(c+a)/b = cos[(C-A)/2]/sin(B/2).
Mollweide's Equations: (a-b)/c = sin[(A-B)/2]/cos(C/2),
(b-c)/a = sin[(B-C)/2]/cos(A/2),
(c-a)/b = sin[(C-A)/2]/cos(B/2).
Other relations: a = b cos(C) + c cos(B),
b = c cos(A) + a cos(C),
c = a cos(B) + b cos(A).
tan[(A-B)/2] = [(a-b)/(a+b)]cot(C/2),
tan[(B-C)/2] = [(b-c)/(b+c)]cot(A/2),
tan[(C-A)/2] = [(c-a)/(c+a)]cot(B/2).
sin(A) = 2K/(bc),
sin(B) = 2K/(ca),
sin(C) = 2K/(ab).
K = sr = sqrt[s(s-a)(s-b)(s-c)],
K = aha/2 = bhb/2 = chc/2,
K = ab sin(C)/2 = bc sin(A)/2 = ca sin(B)/2,
K = a2 sin(B)sin(C)/[2 sin(A)],
= b2 sin(C)sin(A)/[2 sin(B)],
= c2 sin(A)sin(B)/[2 sin(C)].
R = abc/(4K) = a/[2 sin(A)] = b/[2 sin(B)] = c/[2 sin(C)],
r = K/s,
= sqrt[(s-a)(s-b)(s-c)/s],
= c sin(A/2)sin(B/2)/cos(C/2),
= ab sin(C)/(2s),
= (s-c)tan(C/2).
sin(A/2) = sqrt[(s-b)(s-c)/(bc)],
sin(B/2) = sqrt[(s-c)(s-a)/(ca)],
sin(C/2) = sqrt[(s-a)(s-b)/(ab)].
cos(A/2) = sqrt[s(s-a)/(bc)],
cos(B/2) = sqrt[s(s-b)/(ca)],
cos(C/2) = sqrt[s(s-c)/(ab)].
tan(A/2) = sqrt[(s-b)(s-c)/{s(s-a)}] = r/(s-a),
tan(B/2) = sqrt[(s-c)(s-a)/{s(s-b)}] = r/(s-b),
tan(C/2) = sqrt[(s-a)(s-b)/{s(s-c)}] = r/(s-c).
(a+b)/(a-b) = [sin(A)+sin(B)]/[sin(A)-sin(B)] = cot(C/2)/tan[(A-B)/2],
(b+c)/(b-c) = [sin(B)+sin(C)]/[sin(B)-sin(C)] = cot(A/2)/tan[(B-C)/2],
(c+a)/(c-a) = [sin(C)+sin(A)]/[sin(C)-sin(A)] = cot(B/2)/tan[(C-A)/2].
ha = a sin(B)sin(C)/sin(B+C) = a/[cot(B)+cot(C)] = b sin(C) = c sin(B),
hb = b sin(C)sin(A)/sin(C+A) = b/[cot(C)+cot(A)] = c sin(A) = a sin(C),
hc = c sin(A)sin(B)/sin(A+B) = c/[cot(A)+cot(B)] = a sin(B) = b sin(A).
cos(A) + cos(B) + cos(C) = 1 + r/R.
Solving Oblique Triangles
- Case I: You are given any two angles and one side c.
- The third angle is determined from A + B + C =
.
Now the Law of Sines can be used to find b = c sin(B)/sin(C) and a = c sin(A)/sin(C).
- Case II: You are given two sides and the angle opposite one of
them, say a, c, and A.
- Subcase A: a < c sin(A). There is no solution.
- Subcase B: a = c sin(A). There is one solution:
C = /2, B = /2 - A, b = c
cos(A).
- Subcase C: c > a > c sin(A). There are two solutions. Use the
Law of Sines to find sin(C) = c sin(A)/a < 1. There are two angles C and C'
=
- C having that sine, one acute and one
obtuse. Then compute B = - A - C and B'
= - A - C'. Now use the Law of Sines again
to find b = a sin(B)/sin(A) and b' = a sin(B')/sin(A).
The solutions are (a,b,c,A,B,C) and (a,b',c,A,B',C').
- Subcase D: a >= c. There is one solution. Use the Law of Sines
to find sin(C) = c sin(A)/a <= 1. Then angle C must be acute, so it can
be found uniquely from sin(C). Then compute B =
-
A - C. Now use the Law of Sines again to find b = a sin(B)/sin(A).
- Case III: You are given two sides and the included angle, say a, b,
and C.
- You can compute the third side c by using the Law of Cosines. Then the Law
of Sines can be used to find the sines of the other two angles sin(A)
= a sin(C)/c and sin(B) = b sin(C)/c. The angles
opposite the two shortest sides are then acute, and uniquely determined from
their sines, and the third, largest angle is found from A + B + C =
.
- Alternatively, you can use the Law of Tangents. You know that (A+B)/2
= (
-C)/2, which is easily computable. Then
by the Law of Tangents, tan[(A-B)/2] = cot(C/2) (a-b)/(a+b), so
you can find (A-B)/2 uniquely. Then A = ( -C)/2
+ (A-B)/2, and B = ( -C)/2 - (A-B)/2.
Then c = a sin(C)/sin(A).
- Case IV: You are given all three sides.
- You can use the Law of Cosines to find A, then use the Law of Sines to
compute sin(B) = b sin(A)/a and sin(C) = c sin(A)/a.
- Alternatively, you can find r = sqrt[(s-a)(s-b)(s-c)/s], and use tan(A/2)
= r/(s-a) to find A/2, and hence A, and similarly for B and C.
- Alternatively, you can use sin(A/2) = sqrt[(s-b)(s-c)/(bc)] to find A/2
(since A/2 <
/2), and hence A, and
similarly for B and C.
In any case, the results can be checked by using Mollweide's Equations.

Inverse Trigonometric Functions
x = Arcsin(y) ==> y = sin(x), - /2 <= x <= /2,
x = Arccos(y) ==> y = cos(x), 0 <= x <= ,
x = Arctan(y) ==> y = tan(x), - /2 < x < /2,
x = Arccot(y) ==> y = cot(x), 0 < x < ,
x = Arcsec(y) ==> y = sec(x), 0 < x < ,
x = Arccsc(y) ==> y = csc(x), - /2 < x < /2.
y = sin(x) ==> x = Arcsin(y) + 2 n or - Arcsin(y) + 2 n,
y = cos(x) ==> x = Arccos(y) + 2 n or -Arccos(y) + 2 n,
y = tan(x) ==> x = Arctan(y) + n,
y = cot(x) ==> x = Arccot(y) + n,
y = sec(x) ==> x = Arcsec(y) + 2 n or -Arcsec(y) + 2 n,
y = csc(x) ==> x = Arccsc(y) + 2 n or - Arccsc(y) + 2 n,
where n is an arbitrary integer. Arcsin(y) + Arccos(y) = /2,
Arctan(y) + Arccot(y) = /2,
Arcsec(y) + Arccsc(y) = /2.
Arcsin(y) = Arccsc(1/y),
Arccos(y) = Arcsec(1/y),
Arctan(y) = Arccot(1/y), y > 0
Arccot(y) = Arctan(1/y), y > 0
Arcsec(y) = Arccos(1/y),
Arccsc(y) = Arcsin(1/y).
Arcsin[sin(x)] = x - Floor[x/ + 1/2] ,
Arccos[cos(x)] = x - Floor[x/ ] ,
Arctan[tan(x)] = x - Floor[x/ + 1/2] .
sin[Arcsin(y)] = cos[Arccos(y)] = y,
cos[Arcsin(y)] = sin[Arccos(y)] = sqrt[1-y2],
tan[Arcsin(y)] = cot[Arccos(y)] = y/sqrt[1-y2],
cot[Arcsin(y)] = tan[Arccos(y)] = sqrt[1-y2]/y,
sec[Arcsin(y)] = csc[Arccos(y)] = 1/sqrt[1-y2],
csc[Arcsin(y)] = sec[Arccos(y)] = 1/y,
sin[Arctan(y)] = cos[Arccot(y)] = y/sqrt[1+y2],
cos[Arctan(y)] = sin[Arccot(y)] = 1/sqrt[1+y2],
tan[Arctan(y)] = cot[Arccot(y)] = y,
cot[Arctan(y)] = tan[Arccot(y)] = 1/y,
sec[Arctan(y)] = csc[Arccot(y)] = sqrt[1+y2],
csc[Arctan(y)] = sec[Arccot(y)] = sqrt[1+y2]/y,
sin[Arcsec(y)] = cos[Arccsc(y)] = sqrt[y2-1]/y,
cos[Arcsec(y)] = sin[Arccsc(y)] = 1/y,
tan[Arcsec(y)] = cot[Arccsc(y)] = sqrt[y2-1],
cot[Arcsec(y)] = tan[Arccsc(y)] = 1/sqrt[y2-1],
sec[Arcsec(y)] = csc[Arccsc(y)] = y,
csc[Arcsec(y)] = sec[Arccsc(y)] = y/sqrt[y2-1].
sin[2 Arcsin(y)] = 2y sqrt[1-y2],
cos[2 Arccos(y)] = 2y2 - 1,
tan[2 Arctan(y)] = 2y/(1-y2).

Trig Numerical Table
| Degrees |
Radian Measure |
Sin |
Cos |
Tan |
|
Degrees |
Radian Measure |
Sin |
Cos |
Tan |
| 0 |
0.00000 |
0.00000 |
1.00000 |
0.00000 |
|
46 |
0.80285 |
0.71934 |
0.69466 |
1.03553 |
| 1 |
0.01745 |
0.01745 |
0.99985 |
0.01746 |
|
47 |
0.82030 |
0.73135 |
0.68200 |
1.07237 |
| 2 |
0.03491 |
0.03490 |
0.99939 |
0.03492 |
|
48 |
0.83776 |
0.74314 |
0.66913 |
1.11061 |
| 3 |
0.05236 |
0.05234 |
0.99863 |
0.05241 |
|
49 |
0.85521 |
0.75471 |
0.65606 |
1.15037 |
| 4 |
0.06981 |
0.06976 |
0.99756 |
0.06993 |
|
50 |
0.87266 |
0.76604 |
0.64279 |
1.19175 |
| 5 |
0.08727 |
0.08716 |
0.99619 |
0.08749 |
|
51 |
0.89012 |
0.77715 |
0.62932 |
1.23490 |
| 6 |
0.10472 |
0.10453 |
0.99452 |
0.10510 |
|
52 |
0.90757 |
0.78801 |
0.61566 |
1.27994 |
| 7 |
0.12217 |
0.12187 |
0.99255 |
0.12278 |
|
53 |
0.92502 |
0.79864 |
0.60182 |
1.32704 |
| 8 |
0.13963 |
0.13917 |
0.99027 |
0.14054 |
|
54 |
0.94248 |
0.80902 |
0.58779 |
1.37638 |
| 9 |
0.15708 |
0.15643 |
0.98769 |
0.15838 |
|
55 |
0.95993 |
0.81915 |
0.57358 |
1.42815 |
| 10 |
0.17453 |
0.17365 |
0.98481 |
0.17633 |
|
56 |
0.97738 |
0.82904 |
0.55919 |
1.48256 |
| 11 |
0.19199 |
0.19081 |
0.98163 |
0.19438 |
|
57 |
0.99484 |
0.83867 |
0.54464 |
1.53986 |
| 12 |
0.20944 |
0.20791 |
0.97815 |
0.21256 |
|
58 |
1.01229 |
0.84805 |
0.52992 |
1.60033 |
| 13 |
0.22689 |
0.22495 |
0.97437 |
0.23087 |
|
59 |
1.02974 |
0.85717 |
0.51504 |
1.66428 |
| 14 |
0.24435 |
0.24192 |
0.97030 |
0.24933 |
|
60 |
1.04720 |
0.86603 |
0.50000 |
1.73205 |
| 15 |
0.26180 |
0.25882 |
0.96593 |
0.26795 |
|
61 |
1.06465 |
0.87462 |
0.48481 |
1.80405 |
| 16 |
0.27925 |
0.27564 |
0.96126 |
0.28675 |
|
62 |
1.08210 |
0.88295 |
0.46947 |
1.88073 |
| 17 |
0.29671 |
0.29237 |
0.95630 |
0.30573 |
|
63 |
1.09956 |
0.89101 |
0.45399 |
1.96261 |
| 18 |
0.31416 |
0.30902 |
0.95106 |
0.32492 |
|
64 |
1.11701 |
0.89879 |
0.43837 |
2.05030 |
| 19 |
0.33161 |
0.32557 |
0.94552 |
0.34433 |
|
65 |
1.13446 |
0.90631 |
0.42262 |
2.14451 |
| 20 |
0.34907 |
0.34202 |
0.93969 |
0.36397 |
|
66 |
1.15192 |
0.91355 |
0.40674 |
2.24604 |
| 21 |
0.36652 |
0.35837 |
0.93358 |
0.38386 |
|
67 |
1.16937 |
0.92050 |
0.39073 |
2.35585 |
| 22 |
0.38397 |
0.37461 |
0.92718 |
0.40403 |
|
68 |
1.18682 |
0.92718 |
0.37461 |
2.47509 |
| 23 |
0.40143 |
0.39073 |
0.92050 |
0.42447 |
|
69 |
1.20428 |
0.93358 |
0.35837 |
2.60509 |
| 24 |
0.41888 |
0.40674 |
0.91355 |
0.44523 |
|
70 |
1.22173 |
0.93969 |
0.34202 |
2.74748 |
| 25 |
0.43633 |
0.42262 |
0.90631 |
0.46631 |
|
71 |
1.23918 |
0.94552 |
0.32557 |
2.90421 |
| 26 |
0.45379 |
0.43837 |
0.89879 |
0.48773 |
|
72 |
1.25664 |
0.95106 |
0.30902 |
3.07768 |
| 27 |
0.47124 |
0.45399 |
0.89101 |
0.50953 |
|
73 |
1.27409 |
0.95630 |
0.29237 |
3.27085 |
| 28 |
0.48869 |
0.46947 |
0.88295 |
0.53171 |
|
74 |
1.29154 |
0.96126 |
0.27564 |
3.48741 |
| 29 |
0.50615 |
0.48481 |
0.87462 |
0.55431 |
|
75 |
1.30900 |
0.96593 |
0.25882 |
3.73205 |
| 30 |
0.52360 |
0.50000 |
0.86603 |
0.57735 |
|
76 |
1.32645 |
0.97030 |
0.24192 |
4.01078 |
| 31 |
0.54105 |
0.51504 |
0.85717 |
0.60086 |
|
77 |
1.34390 |
0.97437 |
0.22495 |
4.33148 |
| 32 |
0.55851 |
0.52992 |
0.84805 |
0.62487 |
|
78 |
1.36136 |
0.97815 |
0.20791 |
4.70463 |
| 33 |
0.57596 |
0.54464 |
0.83867 |
0.64941 |
|
79 |
1.37881 |
0.98163 |
0.19081 |
5.14455 |
| 34 |
0.59341 |
0.55919 |
0.82904 |
0.67451 |
|
80 |
1.39626 |
0.98481 |
0.17365 |
5.67128 |
| 35 |
0.61087 |
0.57358 |
0.81915 |
0.70021 |
|
81 |
1.41372 |
0.98769 |
0.15643 |
6.31375 |
| 36 |
0.62832 |
0.58779 |
0.80902 |
0.72654 |
|
82 |
1.43117 |
0.99027 |
0.13917 |
7.11537 |
| 37 |
0.64577 |
0.60182 |
0.79864 |
0.75355 |
|
83 |
1.44862 |
0.99255 |
0.12187 |
8.14435 |
| 38 |
0.66323 |
0.61566 |
0.78801 |
0.78129 |
|
84 |
1.46608 |
0.99452 |
0.10453 |
9.51436 |
| 39 |
0.68068 |
0.62932 |
0.77715 |
0.80978 |
|
85 |
1.48353 |
0.99619 |
0.08716 |
11.43005 |
| 40 |
0.69813 |
0.64279 |
0.76604 |
0.83910 |
|
86 |
1.50098 |
0.99756 |
0.06976 |
14.30067 |
| 41 |
0.71558 |
0.65606 |
0.75471 |
0.86929 |
|
87 |
1.51844 |
0.99863 |
0.05234 |
19.08114 |
| 42 |
0.73304 |
0.66913 |
0.74314 |
0.90040 |
|
88 |
1.53589 |
0.99939 |
0.03490 |
28.63625 |
| 43 |
0.75049 |
0.68200 |
0.73135 |
0.93252 |
|
89 |
1.55334 |
0.99985 |
0.01745 |
57.28996 |
| 44 |
0.76794 |
0.69466 |
0.71934 |
0.96569 |
|
90 |
1.57080 |
1.00000 |
0.00000 |
|
| 45 |
0.78540 |
0.70711 |
0.70711 |
1.00000 |
|
|
|
|
|
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All American Security Fasteners
144B W. Walnut Fullerton, Calif. 92634-6280
Tel: 714-525-0608
FAX: 714-525-0628
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